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Form 4 · Chapter 4

Indices, Surds and Logarithms, SPM Additional Mathematics Form 4

Indices, Surds and Logarithms is Chapter 4 of Form 4 Add Math, where you meet three closely linked ideas and the laws that govern them. It has four parts, the laws of indices, the laws of surds, the laws of logarithms, and their applications, and together they build the algebra you will reuse in progressions, the linear law, differentiation and integration.

The key insight is that a logarithm is simply an index seen from the other side.

What this chapter is

Indices, Surds and Logarithms is Chapter 4 of Form 4 Additional Mathematics, and it ties together three ideas that look different on the surface but are really one story about powers. An index (or exponent) records how many times a base is multiplied by itself.

A surd is an exact root such as 2\sqrt{2} that cannot be written as a neat fraction, which turns out to be a power with a fractional index. A logarithm reverses the whole process: it asks what power a base must be raised to in order to reach a given number.

Once you see that a log is just an index viewed from the other direction, the chapter stops being three separate topics and becomes a single, connected skill.

The chapter is organised into four content standards from the KSSM DSKP. You begin with the laws of indices, which let you combine and simplify powers with the same base and extend the meaning of a power to zero, negative and fractional indices.

You then move to the laws of surds, learning to simplify roots, add and subtract like surds, and rationalise a denominator so that no surd is left underneath. Next come the laws of logarithms, where you convert freely between index and logarithm form, apply the product, quotient and power laws, and use change of base.

Finally you bring all three together in applications, problems that mix indices, surds and logarithms in one question.

This is one of the great foundation chapters of the course. The index laws you meet here reappear the moment you differentiate xnx^{n} or integrate a power in Form 5.

Logarithms return in the linear law, where taking logs turns a curved relationship into a straight line you can analyse. Surds show up whenever an exact answer is required in coordinate geometry, trigonometry or when solving quadratics.

Time spent here is repaid many times over, because so much of the later syllabus quietly assumes you can handle powers with confidence.

Because SPM uses analytic scoring, you earn marks for each correct step of a simplification, not only for the final line. Our teachers treat this chapter as a place to build clean, disciplined algebra: change one thing at a time, quote the law you are using, and keep exact values exact rather than rounding early.

A tidy chain of working here is worth real marks, and it is a habit that protects your score in every later chapter that ends in an expression to simplify or an equation to solve.

A short reminder about language. Nothing in this chapter is naturally hard once the definitions are clear; almost every difficulty students meet is a definition that was learned loosely.

Is a0a^{0} really 11? Why does a1a^{-1} mean a reciprocal and not a negative number?

What exactly is logax\log_{a}x asking for? We spend time making these definitions precise, because a firm definition makes the laws feel obvious instead of arbitrary, and obvious laws are the ones you never forget under exam pressure.

Content standards

Indices, Surds and Logarithms is organised into four content standards. These codes and titles come directly from the DSKP, recognise them so you know exactly what a question is testing.

CodeStandardWhat you learn
4.1Laws of IndicesSimplify algebraic expressions using the laws of indices, including zero, negative and fractional indices, and solve real-context problems involving indices.
4.2Laws of SurdsRelate surds to irrational numbers, simplify expressions involving surds, rationalise denominators, and solve problems that combine surds with indices.
4.3Laws of LogarithmsConvert between index and logarithm form, prove and apply the laws of logarithms, use change of base, and simplify logarithmic expressions.
4.4Applications of Indices, Surds and LogarithmsSolve problems that draw on indices, surds and logarithms together, including questions set in a real-life context.

The four standards build on one another in order. Standard 4.1 sets up the rules of powers; standard 4.2 applies those rules to fractional powers written as roots; standard 4.3 turns the index laws inside out to give the log laws; and standard 4.4 asks you to move between all three in a single problem.

Meeting them in sequence, and being fluent with each before the next, is the reliable way through the chapter.

Key ideas

An index is repeated multiplication. In ana^{n}, the number aa is the base and nn is the index, and ana^{n} means aa multiplied by itself nn times.

The laws of indices are the rules for combining powers that share a base, and every one of them is just a shorthand for counting how many factors you have.

The three core laws of indicesMust memorise
am×an=am+n,am÷an=amn,(am)n=amna^{m}\times a^{n}=a^{m+n},\qquad a^{m}\div a^{n}=a^{m-n},\qquad (a^{m})^{n}=a^{mn}
Multiply powers of the same base by adding indices; divide by subtracting; raise a power to a power by multiplying.

Zero, negative and fractional indices extend the idea. The same laws force useful meanings onto powers that are not whole numbers: any non-zero base to the power zero is 11, a negative index is a reciprocal, and a fractional index is a root.

These are not new rules to memorise separately, they are the only definitions that keep the three core laws consistent.

Zero, negative and fractional indicesMust memorise
a0=1,an=1an,amn=amn=(an)ma^{0}=1,\qquad a^{-n}=\dfrac{1}{a^{n}},\qquad a^{\frac{m}{n}}=\sqrt[n]{a^{m}}=\left(\sqrt[n]{a}\right)^{m}

Solving index equations. When an unknown sits in the index, the standard first move is to write both sides as powers of the same base, then equate the indices.

For example 32x1=273^{\,2x-1}=27 becomes 32x1=333^{\,2x-1}=3^{3}, so 2x1=32x-1=3 and x=2x=2. If the two sides cannot be matched to a common base, that is your signal to take logarithms instead.

A surd is an exact irrational root. Numbers such as 2\sqrt{2} and 10\sqrt{10} are irrational, their decimals never terminate or repeat, so leaving them as surds keeps the value exact.

A rational number can be written as a fraction of integers; a surd cannot, which is exactly why we carry it through the working instead of rounding it to a decimal too early.

Laws of surds and simplifying. A root of a product splits into a product of roots, and a root of a quotient splits into a quotient of roots.

You simplify a surd by pulling out the largest perfect-square factor: 90=9×10=310\sqrt{90}=\sqrt{9\times10}=3\sqrt{10}. Only like surds, those with the same number under the root, can be added or subtracted, just as only like terms combine in ordinary algebra.

Laws of surdsMust memorise
ab=ab,ab=ab\sqrt{ab}=\sqrt{a}\,\sqrt{b},\qquad \sqrt{\dfrac{a}{b}}=\dfrac{\sqrt{a}}{\sqrt{b}}

Rationalising the denominator. A tidy answer never leaves a surd underneath.

For a single surd, multiply top and bottom by that surd: 12=22\dfrac{1}{\sqrt{2}}=\dfrac{\sqrt{2}}{2}. For a denominator of the form a±ba\pm\sqrt{b}, multiply by its conjugate aba\mp\sqrt{b}, which uses the difference of two squares to clear the root, for instance 135=3+595=3+54\dfrac{1}{3-\sqrt{5}}=\dfrac{3+\sqrt{5}}{9-5}=\dfrac{3+\sqrt{5}}{4}.

A logarithm is an index in disguise. The statement logax=m\log_{a}x=m means precisely the same thing as am=xa^{m}=x.

The logarithm answers the question "to what power must I raise the base aa to get xx?" Being able to flip instantly between these two forms is the single most valuable habit in the whole chapter.

Definition of a logarithmMust memorise
logax=m    am=x,a>0, a1, x>0\log_{a}x=m \iff a^{m}=x,\qquad a>0,\ a\neq1,\ x>0
The base a is positive and not 1; you can only take the logarithm of a positive number.

Laws of logarithms. Because logs are indices, the index laws translate straight into log laws: multiplying inside a log becomes adding, dividing becomes subtracting, and a power comes out to the front as a multiplier.

Two special values are worth knowing on sight: logaa=1\log_{a}a=1 and loga1=0\log_{a}1=0.

The three laws of logarithmsMust memorise
loga(xy)=logax+logay,logaxy=logaxlogay,logaxn=nlogax\log_{a}(xy)=\log_{a}x+\log_{a}y,\qquad \log_{a}\dfrac{x}{y}=\log_{a}x-\log_{a}y,\qquad \log_{a}x^{n}=n\log_{a}x

Change of base, the one formula the exam gives you. To rewrite a logarithm in a different base, or to evaluate a log your calculator does not have a button for, use change of base.

This result is printed on the SPM formulae page, so you do not have to memorise it, but you must recognise when it is needed. A handy special case that follows from it is logab=1logba\log_{a}b=\dfrac{1}{\log_{b}a}.

Change of base (given in the SPM formulae list)Given in the exam
logab=logcblogca\log_{a}b=\dfrac{\log_{c}b}{\log_{c}a}

What is given and what to memorise. Change of base is the only result from this chapter supplied in the exam.

Every law of indices, every law of surds, the definition of a logarithm and the three log laws must be memorised and, more importantly, understood, because when you understand why each law is true, you can rebuild any one you momentarily forget from the definition of a power.

How it is examined

Indices, Surds and Logarithms can be tested in either written paper. Paper 1 (3472/1) lasts 2 hours and carries 80 marks: Section A has 12 questions worth 64 marks that you answer all of, and Section B has 3 questions worth 16 marks from which you answer 2.

Paper 2 (3472/2) lasts 2 hours 30 minutes and carries 100 marks across Section A (7 questions, 50 marks, answer all), Section B (4 questions, 30 marks, answer 3) and Section C (4 questions, 20 marks, answer 2).

Across both papers the items are limited-response subjective and structured questions, they are marked using analytic scoring, and you sit them with a non-programmable scientific calculator. We do not predict how many marks any single chapter will carry, because that varies from year to year, but the powers, surds and logarithms in this chapter also appear inside progressions, the linear law and calculus, so the skill earns marks well beyond its own share of the paper.

This chapter rewards the show-your-working format. Simplifying a surd, solving an index equation or unwinding a logarithm is naturally a multi-step task, and because the scoring is analytic, each correct application of a law can earn its own mark.

Change one thing per line, name the law you are using, and keep exact values exact until the final answer, a rounded decimal partway through can quietly cost you the marks that a surd or a fraction would have kept.

Exam tip

When an unknown is in the index and both sides share a base, equate the indices; when they do not, take logarithms of both sides. Always check the domain of a logarithm: because you can only take the log of a positive number, any 'solution' that makes an original logarithm undefined must be rejected.

Rationalise every denominator and leave surds exact, writing 22\frac{\sqrt{2}}{2} rather than a rounded 0.707 keeps your answer, and your marks, exact.

Common mistakes

Most marks lost in this chapter come from a handful of avoidable habits. Read these before every practice set until they become second nature.

  • Confusing 'add the indices' with 'multiply the indices'. You add indices when multiplying powers of the same base, am×an=am+na^{m}\times a^{n}=a^{m+n}; you multiply them when raising a power to a power, (am)n=amn(a^{m})^{n}=a^{mn}. Mixing these two up is the single most common index error.
  • Reading a negative index as a negative number. A negative index is a reciprocal, not a sign change: 23=182^{-3}=\dfrac{1}{8}, not 8-8. The power stays positive; it just moves to the denominator.
  • Splitting the surd of a sum. The law splits a product, not a sum: ab=ab\sqrt{ab}=\sqrt{a}\,\sqrt{b} is true, but a+ba+b\sqrt{a+b}\neq\sqrt{a}+\sqrt{b}. Check with numbers, 9+16=5\sqrt{9+16}=5, while 9+16=7\sqrt{9}+\sqrt{16}=7.
  • Adding unlike surds. Only like surds combine: 23+53=732\sqrt{3}+5\sqrt{3}=7\sqrt{3}, but 2+3\sqrt{2}+\sqrt{3} cannot be simplified into a single surd. Simplify each surd first, because two roots that look different may actually be like once reduced.
  • Turning loga(x+y)\log_{a}(x+y) into logax+logay\log_{a}x+\log_{a}y. The product law applies to loga(xy)\log_{a}(xy), a product inside the log, never to a sum. There is no law that breaks up the logarithm of a sum, so leave it alone.
  • Forgetting the domain of a logarithm. You can only take the logarithm of a positive number, so after solving a log equation, substitute each answer back and discard any that would make an original logarithm undefined. Also keep logaxn=nlogax\log_{a}x^{n}=n\log_{a}x distinct from (logax)n(\log_{a}x)^{n}, the power belongs to xx, not to the whole logarithm.

None of these mistakes is about ability, each one is a habit, and habits are fixable. Tick them off one at a time in your practice and your accuracy climbs quickly.

Students who score well here are rarely the fastest; they are the ones who quote the law they are using and keep every value exact.

How to study this chapter

Indices, Surds and Logarithms rewards a steady, in-order approach: each part rests on the one before it. Work through these steps in sequence, then use the resources below to revise and test yourself.

Aim for short, frequent sessions rather than one long cram. A page of index simplifications, then a page of surds, then a page of logs, spread across a fortnight, builds fluency far better than a single marathon.

When a law feels automatic, move on; when it does not, go back to the definition and rebuild it. This quiet, layered practice turns a chapter that can feel abstract into some of your most dependable marks.

  1. 1

    Master the index laws

    Get the three core laws automatic, then practise zero, negative and fractional indices until reciprocals and roots feel natural rather than tricky.

  2. 2

    Move to surds

    Simplify by pulling out perfect squares, add and subtract like surds, and rationalise denominators, including the conjugate case for a±ba\pm\sqrt{b}.

  3. 3

    Learn the logarithm as an index

    Drill converting between logax=m\log_{a}x=m and am=xa^{m}=x both ways until the flip is instant, and memorise logaa=1\log_{a}a=1 and loga1=0\log_{a}1=0.

  4. 4

    Apply the log laws and change of base

    Practise the product, quotient and power laws, then use change of base to evaluate and to rewrite logs in a convenient base.

  5. 5

    Mix, apply and time yourself

    Attempt questions that combine indices, surds and logs in one problem, always checking the domain, then work example sets against the clock.

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Frequently asked questions

How are indices, surds and logarithms connected?

They are three views of the same idea, powers. An index counts how many times a base is multiplied; a surd such as 2\sqrt{2} is a power with a fractional index; and a logarithm is the reverse of an index, since logax=m\log_{a}x=m means exactly am=xa^{m}=x.

Because they share one root idea, the index laws, surd laws and log laws all echo one another.

Which formulae are given in the exam for this chapter?

Only change of base, logab=logcblogca\log_{a}b=\frac{\log_{c}b}{\log_{c}a}, is printed on the SPM formulae page. Every law of indices, every law of surds, the definition of a logarithm and the three log laws must be memorised, though once you understand why each is true, you can rebuild any of them from the meaning of a power.

What is the difference between a surd and a rational number?

A rational number can be written as a fraction of two integers and its decimal either stops or repeats. A surd such as 2\sqrt{2} or 10\sqrt{10} is irrational, its decimal never stops or repeats, so we keep it in surd form to stay exact rather than rounding it to a decimal too early.

When should I take logarithms to solve an index equation?

First try to write both sides as powers of the same base and equate the indices, that is quickest. Only when the two sides cannot share a base, for example 2x=72^{x}=7, do you take logarithms of both sides and use the power law to bring the unknown down from the index.

Source:SRC-DSKP-ENSRC-FORMAT

Written by the spmaddmath.com.my editorial team.· Last updated 5 September 2026

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