Skip to content
spmaddmath.com.my
Tuition

Study

SyllabusFormulasMethodsExam & PapersTools
LocationsPricingBlogOur TeachersContact
EN

Method · Quadratic Functions

How to Solve a Quadratic Inequality

To solve a quadratic inequality, move everything to one side so it compares with zero, find the roots of the matching equation, then use a quick sketch of the parabola to read off where it is above or below the xx-axis.

What this method is for

Solving a quadratic inequality means finding every value of xx that makes a quadratic expression greater than, less than, or equal to zero. Unlike a quadratic equation, which has at most two answers, an inequality has a whole range of answers, usually an interval between the roots, or the two outer regions beyond them.

The method turns the inequality into a picture: find where the parabola meets the xx-axis, then read off where the curve sits above the axis (positive) or below it (negative). This answers questions such as "solve x2x6>0x^2-x-6>0", "find the range of values of xx satisfying x2+2x80x^2+2x-8\le 0", or word problems that require a quantity to stay positive.

It is a core Form 4 Quadratic Functions skill, and it depends directly on factorising and on knowing which way a parabola opens.

Because the answer is a range, the way you write it matters as much as the numbers. A clear sketch keeps the direction of each inequality sign honest and stops the two cases, inside the roots versus outside the roots, from being mixed up.

When to use this method

Reach for this method whenever a question contains a quadratic together with an inequality sign, >>, <<, \ge or \le, and asks for the values of xx that satisfy it. Wording such as "solve the inequality", "find the range of values of xx", or "for what values of xx is the expression positive" is the direct cue.

It is also the final step in problems where an earlier part produces a quadratic condition, for instance after using the discriminant to find a range of kk, or when a length or area must be positive. Because the solution is a set of values rather than a single number, watch for the plural "values".

Quadratic-inequality questions appear in both Paper 1 and Paper 2, often as a short but easily-lost few marks.

The steps

Follow this order so the direction never goes wrong:

  1. 1

    Make one side zero

    Rearrange the inequality so all terms are on one side and the other side is 0, keeping the coefficient of x2x^2 positive if you can.

  2. 2

    Find the critical values

    Solve the matching equation (set the expression equal to zero) by factorising to get the roots. These are the boundary points.

  3. 3

    Sketch the parabola

    Draw a quick parabola opening upward, crossing the xx-axis at the two roots. This shows where the curve is above or below the axis.

  4. 4

    Choose the correct region

    For >0>0 or 0\ge 0, take where the curve is above the axis (outside the roots); for <0<0 or 0\le 0, take where it is below (between the roots).

  5. 5

    Write the solution

    State the range using the correct signs. Use \le or \ge (roots included) for a non-strict inequality, and << or >> (roots excluded) for a strict one.

Keep the x2x^2 coefficient positive

If the coefficient of x2x^2 is negative, multiply through by 1-1 and reverse the inequality sign first. Then every sketch opens upward and the reasoning is the same each time.

Worked example

Try this yourself first, then check each line against the solution.

Q1[3 marks]

Solve the inequality x2+2x80x^2+2x-8\le 0.

Show worked solution

One side is already zero and the coefficient of x2x^2 is positive, so factorise the left-hand side:

x2+2x8=(x+4)(x2)x^2+2x-8=(x+4)(x-2)

The critical values come from setting each factor to zero:

(x+4)(x2)=0x=4 or x=2(x+4)(x-2)=0 \quad\Rightarrow\quad x=-4 \ \text{or}\ x=2

Sketch the parabola. It opens upward (positive x2x^2 coefficient) and crosses the xx-axis at x=4x=-4 and x=2x=2.

The curve is at or below the axis between these two roots.

We want x2+2x80x^2+2x-8\le 0, that is where the curve is on or below the axis, so we take the region between the roots, including the endpoints because the sign is \le:

4x2-4\le x\le 2

Answer

4x2-4\le x\le 2. Check with a test point: at x=0x=0, 02+2(0)8=800^2+2(0)-8=-8\le 0, true, and 00 lies inside the interval.

At the endpoints, (4)2+2(4)8=0(-4)^2+2(-4)-8=0 and 22+2(2)8=02^2+2(2)-8=0, so both are included, exactly as \le requires.

The test-point check is the fastest safeguard. Pick any easy value inside your proposed range, substitute it, and confirm the inequality really holds.

If it does not, you have taken the wrong region and can fix it before writing the final line.

Common mistakes to avoid

  • Choosing the wrong region, taking "between the roots" when the question wants "outside", or the reverse. A quick sketch prevents this every time.
  • Not moving everything to one side first, so the comparison is not really with zero.
  • Forgetting to reverse the inequality sign when multiplying or dividing by a negative number.
  • Mixing up strict and non-strict signs, so the endpoints are wrongly included or excluded. Use ,\le,\ge to include roots and <,><,> to exclude them.
  • Writing the answer as 4x2-4\le x\ge 2 or joining two separate regions with "and"; a single interval uses one continuous chain, and two outer regions use "or".

How a teacher helps you get it right

The step that loses marks is almost always choosing the region, deciding whether the answer is between the roots or outside them. In a one-to-one lesson our teacher has you draw the little parabola every time, so the choice is read off the picture rather than guessed.

Because our teachers are experienced, you get someone who spots whether your slip is the region, a reversed sign, or an included endpoint, and drills just that. Lessons are online and taught in English, while SPM papers are set in both Malay and English, so we make sure you can express the range clearly in either.

We also build the test-point habit, substitute one easy value to confirm the region, so a careless choice never survives to the answer line.

Get 1-to-1 help.

Book a Trial Class

Frequently asked questions

Why does a quadratic inequality give a range instead of single values?

Because you are asking where the whole curve is above or below the axis, not just where it meets the axis. The roots are the boundaries, and every xx in the chosen region satisfies the inequality, so the answer is a range.

How do I know whether to take between the roots or outside them?

Sketch the upward parabola. For <0<0 or 0\le 0 the curve is below the axis between the roots; for >0>0 or 0\ge 0 it is above the axis outside the roots.

A test point confirms the choice.

When are the roots included in the answer?

Include the roots when the sign is \le or \ge, because equality is allowed there. Exclude them when the sign is strict, << or >>.

This changes whether you write, say, 4x2-4\le x\le 2 or 4<x<2-4<x<2.

What if the coefficient of x2x^2 is negative?

Multiply the whole inequality by 1-1 and reverse the inequality sign first. That makes the parabola open upward, so every sketch and every rule reads the same way.

How do I write an answer that is two separate regions?

Join them with "or", for example x<2x<-2 or x>3x>3. Never write a single chain like 3<x<23<x<-2, which describes an empty set and is a common careless error.

Source:SRC-DSKP-EN

Written by the spmaddmath.com.my editorial team.· Last updated 5 September 2026

Ready to get started?

Book a Trial Classfrom RM50/hr · One-hour paid trial · Same-day reply
Book a Trial ClassOne-hour paid trial · Same-day reply