Method · Probability Distribution
Using the binomial distribution
The binomial distribution gives the probability of exactly successes in independent trials with a constant success probability : .
What the binomial distribution is for
The binomial distribution models a situation that is repeated a fixed number of times, where each repetition (a 'trial') has just two outcomes, a 'success' or a 'failure', and the probability of success stays the same every time. Tossing a coin 10 times and counting heads, or checking 5 items and counting how many are faulty, are classic examples.
If is the number of successes, then follows a binomial distribution written , where is the number of trials and is the probability of success in one trial. The formula then gives the probability of exactly successes.
This lets us answer questions such as 'exactly 2', 'at least 3', or 'at most 1' success, and to find the mean and variance .
When to reach for it
Reach for the binomial distribution when a question describes a fixed number of repeated trials and asks for the probability of a certain number of 'successes'. Look for four features: a set number of trials ; each trial has only two outcomes; the trials are independent; and the success probability is the same each time.
Signal phrases include 'in trials', 'each with probability ', 'exactly', 'at least', or 'at most'. If any trial affects the next, for example drawing without replacement so the probability changes, it is not binomial.
When the variable is instead a continuous measurement such as height or mass, you are looking at the normal distribution rather than the binomial.
The method, step by step
- 1
Check the conditions
Fixed trials, two outcomes per trial, independent trials, and a constant success probability .
- 2
Identify n, p and r
State the number of trials , the success probability , and the number of successes you need.
- 3
Write the formula
State .
- 4
Substitute the values
Put , , and into the formula; check the two powers add up to .
- 5
Evaluate
Work out , then the two powers, then multiply the three parts together.
- 6
Combine for 'at least' or 'at most'
Add the separate terms you need, or use the complement, e.g. .
Worked example
In a certain game, the probability of winning any single round is . A player plays 5 independent rounds.
(a) Find the probability that the player wins exactly 2 rounds. (b) State the mean and variance of the number of rounds won.
Show worked solution
(a) The number of wins is binomial with and , so . We want .
Evaluate each part: , , and .
The probability of winning exactly 2 rounds is .
(b) For a binomial distribution the mean is and the variance is .
The mean number of rounds won is and the variance is .
Common mistakes to avoid
- Swapping and , or being unclear about which outcome counts as a 'success'.
- Using the wrong , or writing exponents that do not add up to , the powers of and must total .
- For 'at least one', calculating a long sum instead of using the complement .
- Confusing the mean with the variance , or taking the variance as the standard deviation.
- Rounding or the powers too early, so the final probability drifts off.
How one-to-one teaching helps
The step students most often get wrong is the very first one: checking that the situation really is binomial, and being clear about which outcome is the 'success' that belongs to. In a one-to-one lesson our teachers ask you to say the four conditions aloud and name , and before any calculating begins, so the setup is right every time.
We also drill the complement shortcut for 'at least' questions until it feels natural. Teachers at spmaddmath.com.my are experienced, and lessons are online and taught in English.
To see how we teach the binomial distribution, message us on WhatsApp to arrange a one-hour paid class from RM50/hr at the teacher's rate.
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Book a Trial ClassFrequently asked questions
What are the conditions for a binomial distribution?
There must be a fixed number of trials ; each trial has only two outcomes (success or failure); the trials are independent; and the probability of success is constant across trials. If all four hold, the number of successes is binomial.
How do I find the mean and variance?
For , the mean is and the variance is . The standard deviation is .
Remember the variance always uses the factor , so it is smaller than the mean.
How do I work out 'at least one' success?
It is usually fastest to use the complement: , where . This avoids adding many separate terms.
When is a situation not binomial?
When the trials are not independent or the success probability changes, for example, drawing objects without replacement, since each draw alters what is left. It is also not binomial when the variable is a continuous measurement like length or mass; that is modelled by the normal distribution.
Source:SRC-DSKP-EN