Method · Linear Law
How to reduce a relation to linear form
Rewrite a non-linear relation as by taking logarithms or rearranging, so that plotting the right pair of variables gives a straight line whose gradient and intercept reveal the unknown constants.
What this method is for
Linear Law is about turning a curved relationship between two variables into a straight line. A straight line is easy to draw through data points and its gradient and vertical-axis intercept are easy to measure, so if you can rewrite a relation in the form , you can read the unknown constants straight off the graph.
This method rearranges relations such as or , usually by taking logarithms of both sides, until they match the straight-line shape.
For a power relation, taking of both sides does the job:
Comparing with , you plot against , read the gradient as , and the intercept as .
When to reach for it
Reach for this method when a question gives a relation containing unknown constants together with either experimental data or a described straight-line graph of transformed variables. Phrases such as 'reduce to linear form', 'when is plotted against a straight line is obtained', or 'the graph of against is a straight line' are direct signals.
Choose the transformation from the shape of the relation. A power law or an exponential calls for taking logarithms so the exponent comes down.
A relation like is better handled by dividing through by to reach . Deciding the transformation first tells you exactly what to plot on each axis.
The steps
- 1
Read off the relation and constants
Note the non-linear relation and which constants you must find, for example and in .
- 2
Transform to Y = mX + c
Take of both sides for a power or exponential relation, or rearrange (for example divide by ) so the equation becomes linear.
- 3
Match the parts
Identify , , the gradient , and the intercept by comparing your equation with .
- 4
Read the graph
From the straight-line graph, take the gradient and the vertical-axis intercept.
- 5
Form equations in the constants
Set the gradient equal to its expression and the intercept equal to its expression, then solve for each constant.
- 6
Undo any logarithm
If the intercept was , recover ; state the constants and, if asked, the original relation.
Worked example
The variables and are related by , where and are constants. When is plotted against , a straight line is obtained with gradient and a -intercept of .
Find the values of and .
Show worked solution
Take of both sides of and use the laws of logarithms.
Compare this with the straight-line form , taking and :
The gradient of the line is , and it is given as :
The -intercept is , and it is given as . Undo the logarithm:
So and , which means . As a check, taking of gives , a line of gradient and intercept , exactly as stated.
Common pitfalls
- Reading the intercept as instead of ; you must undo the logarithm with .
- Swapping the axes, being unsure which transformed variable is and which is , which flips gradient and intercept.
- Splitting incorrectly; it equals , not .
- Forgetting to bring the power down with the power law, leaving instead of .
- Mixing up gradient and intercept when matching the equation to .
How a teacher helps
The step that trips students most is the very last one, reading the intercept as rather than , and forgetting to write . In one-to-one lessons our teachers pause exactly at the comparison line, where you match your equation to , and make sure you label , , the gradient and the intercept before touching the numbers.
That single habit removes most Linear Law errors at once. We also check that you take of the whole side, not just part of it.
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Book a Trial ClassFrequently asked questions
Why do we reduce a relation to linear form at all?
Because a straight line is far easier to draw through data and to measure than a curve. Once a relation is written as , the gradient and the vertical-axis intercept can be read directly, and each one gives an equation for an unknown constant.
How do I know whether to take logarithms or to divide through?
Take logarithms when the unknown is an exponent, as in or , so the power comes down. Divide through (for example by ) when the relation is a sum of terms, as in , which becomes .
The intercept of my line is 1, is the constant also 1?
Not if the vertical axis is . If the intercept equals , you must undo the logarithm: .
Always check what the intercept actually represents before quoting the constant.
Do I earn marks for the transformation even without the final constants?
Yes. SPM Add Math uses analytic marking, so correctly reducing the relation to linear form and identifying , , the gradient and the intercept earns method marks, even if a numerical slip changes the final value of a constant.
Source:SRC-DSKP-EN