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Method · Trigonometric Functions

How to prove a trigonometric identity

To prove a trigonometric identity, work on one side only, usually the more complicated one, and transform it, using identities such as sin⁡2θ+cos⁡2θ=1\sin^{2}\theta+\cos^{2}\theta=1, until it becomes exactly the other side. Never move terms across the equals sign.

What this method is for

Proving a trigonometric identity means showing that two expressions are equal for all valid angles, not just solving for one. In the Form 5 Trigonometric Functions chapter of Add Math, these questions ask you to 'show that' or 'prove that' the left-hand side equals the right-hand side.

The method is to start on one side and rewrite it, step by careful step, using algebra and the standard identities, until it matches the other side exactly. Unlike solving an equation, you are not finding a value of the angle, you are demonstrating that the statement is always true.

Each clean line of working earns method marks, so a tidy, logical chain matters as much as the final line.

When to reach for it

Use this method whenever a question says 'prove that' or 'show that' an expression involving sin⁡\sin, cos⁡\cos, tan⁡\tan, sec⁡\sec, cosec⁡\operatorname{cosec} or cot⁡\cot equals another expression. The tell-tale sign is an equals sign with a full expression on each side and no range given, you are not solving for an angle, so there is nothing to 'find'.

Look at both sides first: whichever is more complicated, or contains fractions, is usually the side to start from. If you see 1−sin⁡2θ1-\sin^{2}\theta, 1+tan⁡2θ1+\tan^{2}\theta or a sum of fractions, a Pythagorean identity or a common denominator is almost certainly the next move.

The method, step by step

Pythagorean identity
sin⁡2θ+cos⁡2θ=1\sin^{2}\theta+\cos^{2}\theta=1
  1. 1

    Pick one side

    Choose the more complicated side to work on, usually the one with fractions or higher powers.

  2. 2

    Combine fractions

    If there are fractions, add them over a common denominator.

  3. 3

    Simplify the numerator

    Expand and collect like terms in the numerator carefully.

  4. 4

    Apply an identity

    Use a Pythagorean identity such as 1−sin⁡2θ=cos⁡2θ1-\sin^{2}\theta=\cos^{2}\theta to simplify.

  5. 5

    Convert to target ratios

    Rewrite in the functions that appear on the other side, e.g. 1cos⁡2θ=sec⁡2θ\frac{1}{\cos^{2}\theta}=\sec^{2}\theta.

  6. 6

    Conclude

    State that this side now equals the other side, so the identity is proved.

Work down one side only

Treat the two sides separately. Do not cross-multiply or move terms across the equals sign, that assumes the very thing you are trying to prove.

Transform one side until it looks identical to the other.

Worked example

Q1[4 marks]

Prove that 11+sin⁡θ+11−sin⁡θ=2sec⁡2θ\dfrac{1}{1+\sin\theta}+\dfrac{1}{1-\sin\theta}=2\sec^{2}\theta.

Show worked solution

Start with the left-hand side, which has the fractions. Add them over a common denominator (1+sin⁡θ)(1−sin⁡θ)(1+\sin\theta)(1-\sin\theta):

LHS=(1−sin⁡θ)+(1+sin⁡θ)(1+sin⁡θ)(1−sin⁡θ)\text{LHS}=\frac{(1-\sin\theta)+(1+\sin\theta)}{(1+\sin\theta)(1-\sin\theta)}

Simplify the numerator: (1−sin⁡θ)+(1+sin⁡θ)=2(1-\sin\theta)+(1+\sin\theta)=2. The denominator is a difference of squares: (1+sin⁡θ)(1−sin⁡θ)=1−sin⁡2θ(1+\sin\theta)(1-\sin\theta)=1-\sin^{2}\theta.

LHS=21−sin⁡2θ\text{LHS}=\frac{2}{1-\sin^{2}\theta}

Apply the Pythagorean identity sin⁡2θ+cos⁡2θ=1\sin^{2}\theta+\cos^{2}\theta=1, which gives 1−sin⁡2θ=cos⁡2θ1-\sin^{2}\theta=\cos^{2}\theta:

LHS=2cos⁡2θ\text{LHS}=\frac{2}{\cos^{2}\theta}

Since 1cos⁡2θ=sec⁡2θ\dfrac{1}{\cos^{2}\theta}=\sec^{2}\theta, this becomes 2sec⁡2θ2\sec^{2}\theta, which is the right-hand side. Therefore the identity is proved.

Common mistakes to avoid

  • Treating the identity like an equation and moving terms across the equals sign, this assumes what you are trying to prove.
  • Expanding (1+sin⁡θ)(1−sin⁡θ)(1+\sin\theta)(1-\sin\theta) incorrectly instead of using the difference of squares 1−sin⁡2θ1-\sin^{2}\theta.
  • Using the wrong Pythagorean identity, e.g. writing 1−sin⁡2θ=cos⁡θ1-\sin^{2}\theta=\cos\theta instead of cos⁡2θ\cos^{2}\theta.
  • Confusing sec⁡θ\sec\theta with 1sin⁡θ\frac{1}{\sin\theta}, remember that sec⁡θ=1cos⁡θ\sec\theta=\frac{1}{\cos\theta}.
  • Stopping one step early, before the side you are working on matches the other side exactly.

How one-to-one teaching helps

The habit that costs the most marks is crossing the equals sign, students multiply both sides or shuffle terms, which quietly assumes the result. In a one-to-one lesson our teachers keep you on a single side and ask 'what does this side become next?', so the logic stays honest and every line follows from the last.

We also drill the three Pythagorean identities until choosing the right one is instant. Teachers at spmaddmath.com.my are experienced, and lessons are online and taught in English.

To see how we teach identity proofs, message us on WhatsApp to arrange a one-hour paid class from RM50/hr at the teacher's rate.

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Frequently asked questions

Which side should I start from?

Start from the more complicated side, usually the one with fractions or higher powers, and simplify it towards the other. Working from the busier side gives you more to cancel and makes the path to the answer clearer.

Can I move terms across the equals sign?

No. In a proof you transform one side only until it matches the other.

Moving terms across, or cross-multiplying, assumes the identity is already true, which is exactly what you are trying to show.

Which identities should I know for these proofs?

The Pythagorean identities sin⁡2θ+cos⁡2θ=1\sin^{2}\theta+\cos^{2}\theta=1, 1+tan⁡2θ=sec⁡2θ1+\tan^{2}\theta=\sec^{2}\theta and 1+cot⁡2θ=cosec⁡2θ1+\cot^{2}\theta=\operatorname{cosec}^{2}\theta, plus the definitions tan⁡θ=sin⁡θcos⁡θ\tan\theta=\frac{\sin\theta}{\cos\theta}, sec⁡θ=1cos⁡θ\sec\theta=\frac{1}{\cos\theta} and cosec⁡θ=1sin⁡θ\operatorname{cosec}\theta=\frac{1}{\sin\theta}.

How do I know when the proof is finished?

The proof is complete only when the side you are working on is written in exactly the same form as the other side. Then state clearly that the two sides are equal, so the identity is proved.

Source:SRC-DSKP-EN

Written by the spmaddmath.com.my editorial team.· Last updated 5 September 2026

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