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Calculus Clinic · Integration

Misapplying the power rule to fractional powers

To integrate a power, add one to the index and divide by the new index. With a fractional power like x1/2x^{1/2}, the slip is dividing by the fraction the wrong way: dividing by 32\tfrac{3}{2} means multiplying by 23\tfrac{2}{3}, not by 32\tfrac{3}{2}.

Rewrite roots as powers, raise the index by one, then divide by that new index.

The error

The integration power rule says xndx=xn+1n+1+c\int x^{n}\,dx=\frac{x^{n+1}}{n+1}+c: raise the index by one, then divide by that new index. With a whole-number power this feels routine.

With a fractional power it wobbles in two places. First, students divide by the original index instead of the new one, or forget to add the one at all.

Second, the more damaging slip, they mishandle 'divide by a fraction'. Dividing by 32\tfrac{3}{2} means multiplying by its reciprocal 23\tfrac{2}{3}, but under pressure many write ×32\times\tfrac{3}{2} instead, flipping the fraction the wrong way.

Roots and reciprocals make it worse, because x\sqrt{x} and 1x\tfrac{1}{\sqrt{x}} hide the index before it is even written as a power. The rule itself is short; the arithmetic of fractions is where the marks quietly leak away.

Wrong line, then the fix

Integrate xdx\int\sqrt{x}\,dx. First rewrite the root as a power: x=x1/2\sqrt{x}=x^{1/2}.

The new index is 12+1=32\tfrac{1}{2}+1=\tfrac{3}{2}, and the rule says divide by that new index.

Wrong, multiplied by 3/2 instead of dividing by itMust memorise
x1/2dx=32x3/2+c\int x^{1/2}\,dx=\frac{3}{2}x^{3/2}+c

Dividing by 32\tfrac{3}{2} is the same as multiplying by 23\tfrac{2}{3}, so the coefficient should be 23\tfrac{2}{3}, not 32\tfrac{3}{2}.

Correct, divide by the new index 3/2Must memorise
x1/2dx=x3/23/2+c=23x3/2+c\int x^{1/2}\,dx=\frac{x^{3/2}}{3/2}+c=\frac{2}{3}x^{3/2}+c

Check by differentiating the answer, which should return the integrand. For the correct answer, ddx(23x3/2)=2332x1/2=x1/2=x\frac{d}{dx}\left(\tfrac{2}{3}x^{3/2}\right)=\tfrac{2}{3}\cdot\tfrac{3}{2}x^{1/2}=x^{1/2}=\sqrt{x}.

The wrong answer differentiates to 3232x1/2=94x\tfrac{3}{2}\cdot\tfrac{3}{2}x^{1/2}=\tfrac{9}{4}\sqrt{x}, which is not the integrand, so it fails the check.

The reliable fix

  1. 1

    Rewrite roots and reciprocals as powers

    Turn x\sqrt{x} into x1/2x^{1/2} and 1x\tfrac{1}{\sqrt{x}} into x1/2x^{-1/2} before touching the rule, so the index is visible.

  2. 2

    Add one to the index

    Work out n+1n+1 as a single fraction. For n=12n=\tfrac{1}{2}, the new index is 32\tfrac{3}{2}; for n=12n=-\tfrac{1}{2}, it is 12\tfrac{1}{2}.

  3. 3

    Divide by the NEW index

    Never divide by the original index. Divide the power by n+1n+1.

  4. 4

    Turn 'divide by a fraction' into a multiplication

    Dividing by 32\tfrac{3}{2} means ×23\times\tfrac{2}{3}; dividing by 12\tfrac{1}{2} means ×2\times 2. Flip the fraction and multiply.

  5. 5

    Add +c and differentiate to check

    For an indefinite integral include +c+c, then differentiate your answer, it should give back exactly what you started with.

One line to remember it

Up one, divide by the new power

Add one to the index, then divide by that new index, and dividing by 32\tfrac{3}{2} means times 23\tfrac{2}{3}, never times 32\tfrac{3}{2}.

Practice where the error hides

Q1[4 marks]

Find (6x2x)dx\int\left(6\sqrt{x}-\dfrac{2}{\sqrt{x}}\right)dx.

Show worked solution

Rewrite both terms as powers before integrating: 6x=6x1/26\sqrt{x}=6x^{1/2} and 2x=2x1/2\dfrac{2}{\sqrt{x}}=2x^{-1/2}. Integrate term by term.

For 6x1/26x^{1/2}: the new index is 12+1=32\tfrac{1}{2}+1=\tfrac{3}{2}, so dividing by 32\tfrac{3}{2} means multiplying by 23\tfrac{2}{3}.

6x1/2dx=623x3/2=4x3/2\int 6x^{1/2}\,dx=6\cdot\frac{2}{3}x^{3/2}=4x^{3/2}

For 2x1/22x^{-1/2}: the new index is 12+1=12-\tfrac{1}{2}+1=\tfrac{1}{2}, so dividing by 12\tfrac{1}{2} means multiplying by 22.

2x1/2dx=22x1/2=4x1/2\int 2x^{-1/2}\,dx=2\cdot 2x^{1/2}=4x^{1/2}

Combine, keeping the subtraction from the question, and add the constant.

(6x2x)dx=4x3/24x+c\int\left(6\sqrt{x}-\frac{2}{\sqrt{x}}\right)dx=4x^{3/2}-4\sqrt{x}+c

Check: ddx(4x3/2)=432x1/2=6x\frac{d}{dx}\left(4x^{3/2}\right)=4\cdot\tfrac{3}{2}x^{1/2}=6\sqrt{x} and ddx(4x1/2)=412x1/2=2x\frac{d}{dx}\left(-4x^{1/2}\right)=-4\cdot\tfrac{1}{2}x^{-1/2}=-\dfrac{2}{\sqrt{x}}. Both terms return the integrand, so the answer is correct.

How one-to-one teaching helps

Our teachers slow the fraction step right down, because that is where the marks go. We drill the same three moves, rewrite as a power, add one, divide by the new index, and say 'divide by three-halves means times two-thirds' out loud until the reciprocal stops flipping the wrong way.

In a one-to-one lesson we add the differentiation check so you can catch a wrong coefficient yourself before the paper does. Teachers at spmaddmath.com.my are experienced, and lessons are online and taught in English.

Message us on WhatsApp to arrange a one-hour paid class from RM50/hr at the teacher's rate.

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Frequently asked questions

Do I divide by the old index or the new one?

The new one. Add one to the index first, then divide the power by that new index.

Dividing by the original index is the most common version of this mistake.

How do I integrate 1x\frac{1}{\sqrt{x}}?

Write it as x1/2x^{-1/2}. The new index is 12+1=12-\tfrac{1}{2}+1=\tfrac{1}{2}, and dividing by 12\tfrac{1}{2} means multiplying by 22, so x1/2dx=2x1/2+c=2x+c\int x^{-1/2}\,dx=2x^{1/2}+c=2\sqrt{x}+c.

Why is dividing by 32\frac{3}{2} the same as multiplying by 23\frac{2}{3}?

Because dividing by any fraction means multiplying by its reciprocal, flip the fraction over. So ÷32=×23\div\tfrac{3}{2}=\times\tfrac{2}{3}.

Writing ×32\times\tfrac{3}{2} instead flips it the wrong way and gives the wrong coefficient.

Does this power rule ever fail?

Yes, when the new index would be zero, that is when n=1n=-1. You cannot divide by zero, so x1dx\int x^{-1}\,dx is a separate case and is not part of the fractional-power slip discussed here.

Source:SRC-DSKP-EN

Written by the spmaddmath.com.my editorial team.· Last updated 5 September 2026

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