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Method · Circular Measure

Finding arc length and area of a sector

For a sector with radius rr and angle θ\theta measured in radians, the arc length is s=rθs=r\theta and the area of the sector is A=12r2θA=\frac{1}{2}r^{2}\theta. The angle must be in radians before you substitute.

What this method is for

A sector is the 'pizza slice' region of a circle bounded by two radii and the arc between them. In the Circular Measure chapter you are asked to find the length of that curved edge, the arc length, and the area enclosed by the sector.

Both have short formulas, but they only work when the angle at the centre is measured in radians.

This method also handles related quantities: the perimeter of a sector (the arc plus the two straight radii), and the area of a segment (a sector with a triangle removed). Circular measure questions often combine these with the sine and cosine rules, so a secure grip on s=rθs=r\theta and A=12r2θA=\frac{1}{2}r^{2}\theta is the foundation of the whole chapter.

Because the marking is analytic, showing each substitution clearly earns method marks even if the final arithmetic slips.

When to reach for it

Reach for these formulas whenever a question shows a circle or part of a circle with a marked centre, a radius, and an angle, and asks for a curved length or an area of a slice. Words such as 'arc', 'sector', 'perimeter of the sector' or 'area of the shaded region' are the signals.

Before you substitute, always check the units of the angle. If it is given in radians (often as a decimal like 0.750.75 or a multiple of π\pi), you are ready.

If it is given in degrees, convert first using θrad=θdeg×π180\theta_{\text{rad}}=\theta_{\text{deg}}\times\frac{\pi}{180}. Using degrees directly in s=rθs=r\theta is the most common way to lose marks here, so make the radian check an automatic first step.

The method, step by step

Arc length (θ in radians)
s=rθs=r\theta
Area of sector (θ in radians)
A=12r2θA=\tfrac{1}{2}r^{2}\theta
  1. 1

    Check the angle

    Confirm θ\theta is in radians. If it is in degrees, convert with θrad=θdeg×π180\theta_{\text{rad}}=\theta_{\text{deg}}\times\frac{\pi}{180}.

  2. 2

    List r and θ

    Read the radius rr and the angle θ\theta from the figure, with their units.

  3. 3

    Arc length

    Substitute into s=rθs=r\theta.

  4. 4

    Perimeter, if asked

    Add the two radii to the arc: perimeter =s+2r=s+2r.

  5. 5

    Sector area

    Substitute into A=12r2θA=\frac{1}{2}r^{2}\theta.

  6. 6

    State units

    Give lengths in cm and areas in cm² (or the units used in the question).

Worked example

Q1[5 marks]

A sector of a circle has radius r=8r=8 cm and the angle at the centre is θ=0.75\theta=0.75 radians. Find (a) the arc length, (b) the perimeter of the sector, and (c) the area of the sector.

Show worked solution

The angle is already in radians, so no conversion is needed. Here r=8r=8 and θ=0.75\theta=0.75.

(a) Arc length: s=rθ=8×0.75=6s=r\theta=8\times 0.75=6 cm.

(b) Perimeter of the sector is the arc plus the two radii:

perimeter=s+2r=6+2(8)=6+16=22 cm\text{perimeter}=s+2r=6+2(8)=6+16=22\ \text{cm}

(c) Sector area: A=12r2θ=12×82×0.75A=\frac{1}{2}r^{2}\theta=\frac{1}{2}\times 8^{2}\times 0.75.

Work through it: 82=648^{2}=64, so A=12×64×0.75=32×0.75=24A=\frac{1}{2}\times 64\times 0.75=32\times 0.75=24 cm².

So the arc length is 66 cm, the perimeter is 2222 cm, and the area is 2424 cm².

Common mistakes to avoid

  • Leaving the angle in degrees and substituting straight into s=rθs=r\theta or A=12r2θA=\frac{1}{2}r^{2}\theta. Convert to radians first.
  • Forgetting the 12\frac{1}{2} in the area formula, or squaring the wrong quantity, it is r2r^{2}, not (rθ)2(r\theta)^{2}.
  • Confusing the perimeter of a sector with the arc length: the perimeter also includes the two radii, so add 2r2r.
  • Squaring the radius but forgetting to multiply by θ\theta, or multiplying by θ\theta but not squaring rr.
  • Writing the area in cm instead of cm², or the length in cm², always match the units to the quantity.

How one-to-one teaching helps

The step students most often get wrong is the radian check: they read 6060^{\circ} or 4545^{\circ}, substitute it as if it were radians, and every later answer is wrong. In a one-to-one lesson our teachers build the habit of circling the angle and asking 'radians or degrees?'

before anything else, so the conversion becomes automatic. We also keep arc length, perimeter and area clearly separated so you never mix the formulas.

Because your working is shown line by line, each substitution earns its method mark. Teachers at spmaddmath.com.my are experienced, and lessons are online and taught in English.

To see how we teach circular measure, message us on WhatsApp to arrange a one-hour paid class from RM50/hr at the teacher's rate.

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Frequently asked questions

Why must the angle be in radians for these formulas?

The formulas s=rθs=r\theta and A=12r2θA=\frac{1}{2}r^{2}\theta are derived using radian measure, where an angle of 11 radian cuts off an arc equal to the radius. If you use degrees, the proportions no longer match and the answers are wrong.

Always convert degrees to radians first using θrad=θdeg×π180\theta_{\text{rad}}=\theta_{\text{deg}}\times\frac{\pi}{180}.

How do I find the perimeter of a sector?

The perimeter of a sector is the curved arc plus the two straight radii: perimeter =s+2r=rθ+2r=s+2r=r\theta+2r. A common slip is to give only the arc length ss and forget the two radii, so always add 2r2r when the question asks for the perimeter.

What is the difference between a sector and a segment?

A sector is bounded by two radii and an arc, the whole 'slice'. A segment is the smaller region cut off by a chord, i.e. a sector with the triangle formed by the two radii removed.

To find a segment area, find the sector area 12r2θ\frac{1}{2}r^{2}\theta and subtract the triangle area 12r2sinθ\frac{1}{2}r^{2}\sin\theta.

Can I use these formulas if only the diameter is given?

Yes, but first find the radius: the radius is half the diameter, r=d2r=\frac{d}{2}. Then substitute rr into s=rθs=r\theta and A=12r2θA=\frac{1}{2}r^{2}\theta as usual.

Substituting the diameter by mistake is a frequent error, so read the figure carefully.

Source:SRC-DSKP-EN

Written by the spmaddmath.com.my editorial team.· Last updated 5 September 2026

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