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Chapter · Indices, Surds & Logarithms

Making sense of logarithms in Add Math

A logarithm looks intimidating but it is really just an exponent wearing a different outfit. logax=y\log_{a} x = y is only another way of writing ay=xa^{y} = x.

Once you read a log as "what power do I raise the base to?", the laws stop being random rules and start making sense.

What a logarithm actually is

Most students meet the word "logarithm" and quietly panic, because it sounds far more advanced than it is. The truth is friendlier: a logarithm is just an exponent, a power, asked about from the other direction.

Every logarithm is really asking one plain question: what power do I raise the base to, to get this number?

So log28=3\log_{2} 8 = 3 simply says "the power you raise 22 to, in order to get 88, is 33", because 23=82^{3} = 8. The little number written below, here 22, is called the base.

Read every log that way and it stops being a mystery symbol and becomes a question you can answer.

logax=yay=x\log_{a} x = y \quad\Longleftrightarrow\quad a^{y} = x

That double-headed arrow is the single most important line in the whole chapter. If you can flip fluently between the two sides, the log form and the index form, most log problems become index problems you already know how to handle.

Logs and indices are the same relationship, seen two ways

In the Add Math syllabus, logarithms sit in the same chapter as indices and surds, and that is not an accident. Indices and logarithms are two views of a single relationship between three numbers, a base, a power, and a result.

Indices start from the base and the power and ask for the result. Logarithms start from the base and the result and ask for the power.

Because they describe the same relationship, they are inverses of each other. Two facts follow immediately from the definition and are worth knowing on sight:

  • loga1=0\log_{a} 1 = 0, because anything to the power 00 is 11.
  • logaa=1\log_{a} a = 1, because a base to the power 11 is itself.

Keeping the index picture in mind is what stops the log laws feeling arbitrary. Every log law below is really an index law you already trust, translated into log language.

The laws of logarithms (and where they come from)

There are three laws that do almost all the work, and each mirrors an index law. Because multiplying powers of the same base adds their exponents, multiplying inside a log adds the logs:

loga(xy)=logax+logay\log_{a}(xy) = \log_{a} x + \log_{a} y

In the same way, dividing inside a log subtracts, because dividing powers subtracts their exponents:

loga ⁣(xy)=logaxlogay\log_{a}\!\left(\frac{x}{y}\right) = \log_{a} x - \log_{a} y

And a power inside a log comes out to the front as a multiplier, this is the law that quietly does the heavy lifting when you solve equations:

logaxn=nlogax\log_{a} x^{n} = n \log_{a} x

There is one more tool you will lean on: change of base. Your calculator is a non-programmable scientific calculator, and it only has a log\log button for base 1010 (and a natural log).

To evaluate a log in another base, rewrite it:

logab=logcblogca\log_{a} b = \frac{\log_{c} b}{\log_{c} a}

For instance, log25=log105log102\log_{2} 5 = \dfrac{\log_{10} 5}{\log_{10} 2}, which your calculator can now handle directly.

Using logs to solve equations you couldn't before

Here is where logs earn their place in the paper. Suppose you need to solve 3x=203^{x} = 20.

The unknown is stuck up in the exponent, so ordinary algebra cannot reach it. Taking the logarithm of both sides frees it, because the power law brings the xx down to the front:

log3x=log20    xlog3=log20    x=log20log3\log 3^{x} = \log 20 \;\Rightarrow\; x \log 3 = \log 20 \;\Rightarrow\; x = \frac{\log 20}{\log 3}

From there the calculator finishes the job. Notice the shape of it: the log did not "solve" the equation by magic, it turned a problem you could not touch into division you can.

That is the pattern behind almost every log question in Add Math.

The mistakes that quietly cost marks

Most lost marks in this chapter come from a small number of tempting-but-wrong moves. Knowing them in advance is worth more than any amount of extra practice on the parts you already do correctly.

The number one error

log(x+y)\log(x + y) is not logx+logy\log x + \log y. The addition law is about a product inside the log, log(xy)\log(xy), never a sum.

There is no law that breaks apart the log of a sum, leave it alone.

  • logxlogy\dfrac{\log x}{\log y} is not logxlogy\log x - \log y. Subtraction comes from log ⁣(xy)\log\!\left(\dfrac{x}{y}\right); a fraction of two separate logs is just change of base.
  • The power law needs the power to sit on the whole argument: logx2\log x^{2} becomes 2logx2\log x, but (logx)2(\log x)^{2} does not, those are different objects.
  • You can only take the log of a positive number, so always check that any answer keeps the inside of every log positive.

Why the working matters here

Log questions run across Paper 1 (2 hours, 80 marks) and Paper 2 (2 hours 30 minutes, 100 marks), with no Paper 3. Marking is analytic, so each correct law you apply is a scorable step.

Writing which law you used on each line protects those method marks even if the final number slips.

How one-to-one teaching can help

Logarithms are a chapter that clicks the moment the index picture behind them clicks, and stays confusing for as long as they are memorised as loose rules. Working one-to-one, a teacher can watch how you read a log, catch the exact place the index connection is missing, and rebuild it so the laws feel obvious rather than arbitrary.

Our teachers are experienced; lessons are online and taught in English, while the SPM papers are set bilingually in Bahasa Melayu and English.

If logs are a sticking point, you are welcome to begin with a one-hour paid trial class at the teacher's own rate (from RM50 per hour, depending on experience). We won't promise a grade, but we can help you turn logarithms from a source of dread into one of the more dependable marks on your paper.

Get 1-to-1 help.

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Frequently asked questions

What is a logarithm in plain words?

It is an exponent asked about backwards. logax\log_{a} x answers the question "what power do I raise aa to, to get xx?"

So log28=3\log_{2} 8 = 3 because 23=82^{3} = 8. Reading every log as that question is the fastest way to stop finding them confusing.

Why do we even need logarithms?

They let you solve equations where the unknown is stuck in the exponent, like 3x=203^{x} = 20, which ordinary algebra cannot reach. Taking logs of both sides brings the power down to the front, turning it into simple division you can finish on a calculator.

Is log(x+y)\log(x + y) the same as logx+logy\log x + \log y?

No, this is the most common mistake in the chapter. The addition law applies to a product inside the log: log(xy)=logx+logy\log(xy) = \log x + \log y.

There is no law that splits the log of a sum, so log(x+y)\log(x + y) stays as it is.

My calculator only has a base-10 log button, how do I do other bases?

Use change of base: logab=log10blog10a\log_{a} b = \dfrac{\log_{10} b}{\log_{10} a}. For example log25=log105log102\log_{2} 5 = \dfrac{\log_{10} 5}{\log_{10} 2}, which your non-programmable scientific calculator can evaluate directly.

Source:SRC-FORMAT

Written by the spmaddmath.com.my editorial team.· Last updated 5 September 2026

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